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[tex] \frac{10 \sqrt{3} }{ \sin(60) } = \frac{ab}{ \sin(45) } \\ \frac{10 \sqrt{3} }{ \frac{ \sqrt{3} }{2} } = \frac{ab}{ \frac{ \sqrt{2} }{2} } \\ 5 \sqrt{6} = \frac{ab \sqrt{3} }{2} \\ ab = \frac{10 \sqrt{6} }{ \sqrt{3} } = 10 \sqrt{2} [/tex]