Akar akar persamaan kuadrat 2×^2 + 5x + 7 = 0 adalah alfa dan beta. Nilai alfa/beta + beta/alfa =

jawab

2x² + 5x + 7 = 0
a=2
b= 5
c= 7

α+β = -b/a = - 5/2
α.β = c/ = 7/2

α/β + β/α = (α²+β²)/ αβ = {(α+ β)² - 2αβ}/(αβ) = (-5/2)² - 2(7/2) / (7/2)
= (25/4 - 7) /(7/2)
= 2/7 (25/4 - 7)
= 2/7 (- 3/4)
= - 3/14