Bentuk Sederhana dari 4 akar 6 ( 3 akar 12 - akar 18 + 2 akar 2 ) hai guys jwb ya... makasih ya yg udh jwb

[tex]=4 \sqrt{6}\ (3 \sqrt{12}- \sqrt{18}+2 \sqrt{2}) \\ \\=4 \sqrt{6}\ (3 \sqrt{(3 \times 4)}- \sqrt{(2 \times 9)}+2 \sqrt{2}) \\ \\=4 \sqrt{6}\ (3 \times 2 \times \sqrt{6}- 3 \times \sqrt{2}+2 \sqrt{2})\\ \\=4 \sqrt{6}\ (6 \sqrt{6}- 3 \sqrt{2}+2 \sqrt{2})\\ \\=(4 \sqrt{6} \times 6 \sqrt{6})- (4 \sqrt{6} \times (3 \sqrt{2} + 2\sqrt{2}))\\ \\=(24 \times6)-(4 \sqrt{6} \times 5 \sqrt{2}) \\ \\ =144-(20 \sqrt{12})\\ \\ =144-(20 \sqrt{4 \times 3}) \\ \\ =144-40 \sqrt{3} [/tex]

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