Dketahui deret geometri 4+2+1+1/2+..... a) tentukan rasio b) tentukan Suki ke-12 c) hitunglah 12 suku pertamanya

a)rasio=1/2
b)U12=ar^11
=(4)(1/2)^11
=(2^2)((2^-1)^11)
=(2)^2-11
=(2)^-9
=1/512
C)S12=(a(1-r^n))/(1-r)
=(4(1-(1/2)^12)/(1-1/2)
=(4(1-(2^-12))/(1/2)
=(4(1-(1/4096))/(1/2)
=(4(4095/4096))/(1/2)
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