tolong di jawab ya pakai caranya makasih

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[tex] {6}^{3} \div {2}^{3} + \sqrt[3]{27} \\ = \frac{ {6}^{3} }{ {2}^{3} } + \sqrt[3]{3 \times 3 \times 3} \\ = {3}^{3} + \sqrt[3]{ {3}^{3} } \\ = 27 + 3 \\ = 30[/tex]