integral dari (2x-1)^- 3

jawab

u = 2x - 1
du = 2 dx
dx = 1/2 du

∫ (2x-1)⁻³ dx =  ∫ 1/2 u⁻³ du

= 1/2 . (-1/2) u⁻² + c

= - 1/4 u⁻² + c

=  - 1/ (4u²) + c

= -1/ (4 (2x-1)²) + c