tolong jawab sekarang karena sangat mendadak

Soal No. 16
g (x) = ax + 6
h (x) = x² - ax + (a + 5)

Jika g (-3) = 9; h(x) =?

g(-3) = -3a + 6 = 9
            -3a = 9 - 6
            -3a = 3
               a = -1
h (x) = x² - (-1)x + (-1 + 5)
         = x² + x + 4.................Jawaban (D)

Soal No. 17
c : d = 2 : 5 ⇒ d = 5 maka c = 2
gradien garis (m) = k

Titik A = (c - 1, d + 4) ⇒ (2 - 1 , 5 + 4) ⇒ (1 , 9)
Titik B = (2c - 1 , 3d + 4) ⇒ (2(2) - 1 , 3(5) + 4) ⇒ (4 - 1 , 15 + 4) ⇒ (3 , 19)
x₁ = 1 , y₁ = 9
x₂ = 3 , y₂ = 19

[tex]k = \frac{y_2-y_1}{x_2-x_1} \\ \\ k= \frac{19-9}{3-1} \\ \\ k= \frac{10}{2} \\ \\ k=5 [/tex]

Jawaban (B)

***Semoga Terbantu***