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Matematika
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tolong bantu jawab kak
1 Jawaban
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1. Jawaban Arkan5283
Mapel : Matematika
Bab : Akar dan Pangkat
[tex]6 \sqrt[4]{6} \times 6 ^{2 \frac{2}{3} } \\ = \sqrt[4]{(6^{4} \times 6) } \times6 ^{ \frac{8}{3} } \\ = \sqrt[4]{6 ^{4 + 1} } \times 6 ^{ \frac{8}{3} } \\ = \sqrt[4]{6 ^{5} } \times 6 ^{ \frac{8}{3} } \\ = 6 ^{\frac{5}{4} } \times 6 ^{ \frac{8}{3} } \\ = 6 ^{ \frac{5}{4} + \frac{8}{3} } \\ = 6 ^{ \frac{47}{12} } \\ = \sqrt[12]{6 ^{47} } \\ = \sqrt[12]{6 ^{36} \times 6 ^{11} } \\ = \sqrt[12]{6 ^{36} } \times \sqrt[12]{6 ^{11} } \\ = 6 ^{3} \times \sqrt[12]{6^{11} } \\ = 216 \times \sqrt[12]{6 ^{11} } \\ = 216 \sqrt[12]{6 ^{11} } [/tex]
Jawaban : D. 216 ¹²√6¹¹
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