bantu jawab ya kak :)

[tex] {( \frac{1}{3})}^{2} = {3}^{ - 2} \\ \sqrt{ {3}^{2x + 1} } = {3}^{ \frac{1}{2}(2x + 1)} = {3}^{x + \frac{1}{2} } \: maka \\ {3}^{ - 2} . {3}^{x + \frac{1}{2} } = {3}^{x - \frac{3}{2}} ={3}^{3} \\ x - \frac{3}{2} = 3 \\ x = 3 + \frac{3}{2} = 4 \frac{1}{2} [/tex]