Tentukan persamaan garis yang melalui titik (-2,3) dan (1,1)

Rumus :
y-y1/y2-y1 = x-x1/x2-x1

Jawab :
y-3/1-3 = x-(-2)/1-(-2)
y-3/-2 = x+2/3
-2(x+2) = 3(y-3)
-2x-4 = 3y-9
-2x-3y = 4-9
-2x-3y = -5
-2x-3y+5 = 0

semog membantu:)

[tex](x1,y1) = ( - 2,3) \\ (x2,y2) = (1,1) \\ \\ \frac{x - x1}{x2 - x1} = \frac{y - y1}{y2 - y1} \\ \frac{x - ( - 2)}{1 - ( - 2)} = \frac{y - 3}{1 - 3} \\ \frac{x + 2}{1 + 2} = \frac{y - 3}{1 - 3} \\ \frac{x + 2}{3} = \frac{y - 3}{ - 2} \\ - 2(x + 2) = 3(y - 3) \\ - 2x - 4 = 3y - 9 \\ - 2x - 3y = - 9 + 4 \\ - 2x - 3y = - 5 \\ 2x + 3y = 5[/tex]