tolong jawab yah soalnya mau kumpulin besok
Matematika
margaretha12090
Pertanyaan
tolong jawab yah soalnya mau kumpulin besok
2 Jawaban
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1. Jawaban Anonyme
jawab
1)
a. Keliling = 3/4 keliling lingkaran + 2(r) cm
= 3/4 ( 2 π r ) + 2 r
= 3/4 (2 x 3,14 x 10) + 2(10)
= 4,71 + 20
= 24,71 cm
b. Luas = 3/4 luas lingkaran
L = 3/4 ( π r²)
= 3/4 (3,14)(10²)
= 235,5 cm²
2. r lingkaran = 1/2 (10)= 5
Keliling = 4(r) + 1/2 keliling lingkaran= 4r + 1/2 (2 πr)
K= 4(5) + 1/2 (2)(3,14)(5)
K = 20 + 15,7
K = 35,7 cm
Luas = luas persegi - luas 1/2 lingkaran
L = 10 x 10 - 1/2 (3,14)(5)²
L = 100 - 39,25
L = 60,75 cm
3. gambar anggap persegi, s= 80 cm
r lingkaran = 21 cm
Keliling = 4(80- 2(r) + keliling lingkaran
K = 4(80 -2(21)) + 2 (22/7)(21)
K = 4(80-42) + 2(66)
K = 4(38) + 132
K = 152 + 132
K = 284 cm
Luas = luas persegi - luas lingkaran
L = 80 x 80 - 22/7 (21)²
L = 6.400 - 1.386
L = 5.014 cm² -
2. Jawaban ZuhMahaGuru
1.
a. K 3/4 lingkaran dengan r = 10 cm
K = 3/4 × 2 . π . r
K = 3/4 × 2 . 3,14 . 10
K = 3/4 × 62,8
K = 47,1 cm
b. L = 3/4 × π r^2
3/4 × 3,14 × 10^2
3/4 × 314
235,5 cm2
2.
a.K lingkaran = 1/2 . 2 . π .r
1/2 . 2 . 3,14 . 5
3,14 . 5 = 15,7 cm
K persegi = 4 × s
4 × 10 = 40 cm
K diarsir = 40 - 15,7 = 24,3 cm
b. L lingkaran = 1/2 . π r^2
1/2 . 3,14 × 5^2
1/2 . 78,5 = 39,25 cm2
L persegi = s × s
10 × 10 = 100 cm2
L diarsir = 100 - 39,25 = 60,75 cm2
3.
a. K lingkaran = 2 . π . r
2 . 22/7 . 7 = 44 cm
K persegi panjang = 2 ( p + l )
2 ( 80 + 21 ) = 2 . 101 = 202 cm
K diarsir = 202 - 44 = 158 cm
b. L lingkaran = π r^2
22/7 . 7 .7 = 154 cm2
L persegi panjang = p × l
80 × 21 = 1.680 cm2
L diarsir = 1.680 - 154 = 1.526 cm2