[tex]7 \times + 3y = 9.....(1) \\ 4 \times - 5y = 32.....(2) \\ tlong \: \:substitusi \: [/tex]
Matematika
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Pertanyaan
[tex]7 \times + 3y = 9.....(1) \\ 4 \times - 5y = 32.....(2) \\ tlong \: \:substitusi \: [/tex]
2 Jawaban
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1. Jawaban dharmawan14
7x + 3y = 9
3y = -7x +9
y = (-7x + 9)/3....(1)
4x - 5y = 32....(2)
subsitusikan (1) ke (2)
4x -5 (-7x +9)/3 = 32. (kalikan 3)
12x -5(-7x +9) = 96
12x +35x - 45 = 96
47x = 96 + 45
47x = 141
x = 141/47
x = 3
dari (1), y = (-7x+9)/3
y = (-7.3 +9)/3
y = (-21+9)/3
y = -12/3
y = -4
HP ,= { (3, -4) } -
2. Jawaban Noellmantap
== Jawaban ==
{7 × 3y = 9 (1)
{4 × -5y = 32 (2)
Subtitusi (1) dan (2)
(1) 28 × 12y = 36
(2) 28 × -35y = 224
(1) - (2)
-23y = -188
y = 188/23
y = 8,17
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