Matematika

Pertanyaan

F:x->px^2+qx
F(2)=-2
F(-2)=10
Tentukan nilai p dan q ?

1 Jawaban

  • F(x) = px² + qx

    F(2) = -2
    p(2)² + q(2) = -2
    4p + 2q = -2
    • 2p + q = -1

    F(-2) = 10
    p(-2)² + q(-2) = 10
    4p - 2q = 10
    • 2p - q = 5

    -Eliminasi-
    2p + q = -1
    2p - q = 5 -
    ----------------
    2q = -6
    q = -3
    p = 1

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