tolong jawab nomor 3 yang a aja pakai jalan yang jelas

a) x^2 -2px -p +2 = 0
akar kembar, maka D = 0 (D = b^2-4ac)
(-2p)^2 - 4.1.(-p+2) = 0
4p^2 +4p -8 = 0
p^2 + p - 2 = 0
(p +1)(p -2) = 0
p + 1 = 0 atau p - 2 = 0
p = -1 atau p = 2
b) x^2 +2px -x + p^2 -3p -4 = 0
x^2 +(2p -1)x + (p^2 -3p -4) = 0
(2p -1)^2 -4.1(p^2 -3p -4) = 0
4p^2 -4p +1 -4p^2 +12p +16 = 0
8p +17 = 0
p = 17/8
p = 2 1/8.