jika bilangan bulat bukan 0 maka a ^0 =1 [tex]1. \: {25}^{0} \\ 2. \: {2x}^{0} \\ 3. \: (8p) ^{0} \\ 4. \: 2(9a) ^{0} \\ 5. \: - 5p^{0} \\ 6. \: 2x^{0} + ( - 4p
Matematika
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Pertanyaan
jika bilangan bulat bukan 0 maka a ^0 =1
[tex]1. \: {25}^{0} \\ 2. \: {2x}^{0} \\ 3. \: (8p) ^{0} \\ 4. \: 2(9a) ^{0} \\ 5. \: - 5p^{0} \\ 6. \: 2x^{0} + ( - 4p^{0}) \\ 7. \: \frac{6a ^{0} }{2x ^{0} } \\ 8. \: \frac{ - 8x ^{0} }{0} \\ 9. \: 12x \:^{0} - 3a^{0} \\ 10. \: 9a^{2} + 3a^{0} - a^{2}[/tex]
tolong di jawab pake foto / uraian yg jelas dan kalo ada rumusnya tolong di pake ya :)
[tex]1. \: {25}^{0} \\ 2. \: {2x}^{0} \\ 3. \: (8p) ^{0} \\ 4. \: 2(9a) ^{0} \\ 5. \: - 5p^{0} \\ 6. \: 2x^{0} + ( - 4p^{0}) \\ 7. \: \frac{6a ^{0} }{2x ^{0} } \\ 8. \: \frac{ - 8x ^{0} }{0} \\ 9. \: 12x \:^{0} - 3a^{0} \\ 10. \: 9a^{2} + 3a^{0} - a^{2}[/tex]
tolong di jawab pake foto / uraian yg jelas dan kalo ada rumusnya tolong di pake ya :)
1 Jawaban
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1. Jawaban Anonyme
jawab
25⁰= 1
2x⁰ = 2(1)= 2
(8p)⁰ = 1
2(9a)⁰ = 2 (1)= 2
-5p⁰ = -5(1) = - 5
2x⁰ + (-4 p⁰) = 2(1)+ (-4) = 2-4 = -2
6a⁰/2a⁰ = 6(1) / 2(1) = 6/2 = 3
-8x⁰/o = -8(1)/ 0 = -8/0 = ~
12 x⁰ - 3a⁰ = 12(1) - 3(1)= 12 - 3= 9
9a² + 3 a⁰ - a² = 9 a² + 3(1) - a² = 9a² - a² + 3 = 8a² + 3