Matematika

Pertanyaan

menghitung tabung diameter 5 dan tinggi 5

2 Jawaban


  • [tex]v = \pi \: {r}^{2}t \\ = 3.14 \times {2.5}^{2} \times 5 \\ = 9812.5 {cm}^{3} [/tex]

    [tex]lp = 2\pi \: r \: (r + t) \\ = 2 \times 3.14 \times 2.5(2.5 + 5) \\ = 15.7 \times 7.5 \\ = 117.75 {cm}^{2} [/tex]
  • V = πr^2t
    = 22/7 x 2,5 x 2,5 x 5
    = 2,8 x 12,5
    = 35

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