Matematika

Pertanyaan

1. sederhanakanlah pecahan bentuk aljabar berikut!
a. 36x³ - 6x² / 6x
b. 18x²y³z⁵ + 12xy³z² - 6xy³z / 6xy²z

2. selesaikanlah!
a. 7x² / 4 : 21x / 16
b. x²y² / 12z : xz² / 15y²
c. 4 / x³ × x² / 3 : 8 / xy
d. (x²y² / 3z)² : (2xy³ / 6z)³ × (x²z² / yz)²

makasih sebelumnya^^
pls bantu:(

1 Jawaban

  • [tex]1a.)\ \frac{36x^3-6x^2}{6x} =\frac{6x\times(6x^2-x)}{6x}= 6x^2-x \\ \\ 1b.)\ \frac{18x^2y^3z^5+12xy^3z^2-6xy^3z}{6xy^2z}=\frac{6xy^2z(3xyz^4+2yz-y)}{6xy^2z}=3xyz^4+2yz-y[/tex]

    [tex]2a.)\ (\frac{7x^2}{4}\div\frac{21x}{6})=(\frac{7x^2}{4}\times\frac{6}{21x})=(\frac{x}{4}\times\frac{6}{3})=(\frac{x}{4}\times2)=\frac{1}{2} x\\ \\2b.)\ \frac{x^2y^2}{12z}\div \frac{xz^2}{15y^2}=(\frac{x^2y^2}{12z}\times\frac{15y^2}{xz^2})=(\frac{xy^2}{4z}\times\frac{5y^2}{z^2})=(\frac{5xy^4}{4z^3})=\frac{5}{4}xy^4z^{-3} \\ \\ 2c.)\ \frac{4}{x^3}\times \frac{x^2}{3}\div \frac{8}{xy}=( \frac{4}{3x^2}\times \frac{xy}{8})=(\frac{y}{6x})=\frac{1}{6}x^{-1}y [/tex]

    [tex]2d.)\ (x^2y^2 / 3z)^2\div(2xy^3 / 6z)^3\times(x^2z^2 / yz)^2\\ \\=(\frac{x^2y^2}{3z})^2\div (\frac{2xy^3}{6z})^3\times (\frac{x^2z^2}{yz})^2\\ \\=(\frac{x^4y^4}{9z^2})\div (\frac{8x^3y^9}{216z^3})\times (\frac{x^4z^4}{y^2z^2})\\ \\=(\frac{x^4y^4}{9z^2})\times(\frac{216z^3}{8x^3y^9})\times (\frac{x^4z^4}{y^2z^2})\\ \\=( \frac{216}{72})x^{(4-3+4)}y^{(4-9-2)}z^{(-2+3-2+4)} \\ \\ =3x^5y^{-11}z^3 [/tex]

    ***Semoga Terbantu***

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