dik ph asam lemah monoprotik 4 maka konsentrasi ion OH- dlm larutan adalah?

pOH + pH = 14
pOH = 14 - 4 = 10
pOH = -log[OH^-]
10 = -log[OH^-]
[OH^-] = 10^-10

Basa Monoprotik → OH^- sebanyak 1

XOH → X^+ + OH^-

[OH^-] = 10^-10 M