Matematika

Pertanyaan

f(x) = x + 2
g(x) = [tex]x^{2}[/tex]
h(x) = 2 log x
Tentukan : a.[tex](fogoh)^{-1} (4)[/tex] ....?
b.[tex](gohof)^{-1} (2)[/tex] ....?

1 Jawaban

  • ^ = pangakat

    f(x) = x + 2
    g(x) = x²
    h(x) = 2 log x

    (fogoh) (x) = (2 log x)² + 2
    (fogoh) (x) = 2 log² x + 2
    y = 2 log² x + 2
    log² x = (y - 2) / 2
    log x = √(y - 2) / 2
    x = 10^√(y - 2) / 2
    (fogoh) -¹(x) = 10^√(x - 2) / 2
    (fogoh) -¹ (4) = 10^√(4 - 2) / 2
    (fogoh) -¹ (4) = 10^1
    (fogoh) -¹(4) = 10

    (gohof) (x) = (2 log (x + 2))²
    (gohof) (x) = log² (x + 2)²
    y = log² (x + 2)²
    log (x + 2)² = √y
    (x + 2)² = 10^√y
    x + 2 = √10^√y
    x = -2 + √10^√y
    (gohof) -¹(x) = -2 + √10^√x
    (gohof) -¹(2) = -2 + √10^√2

    Maaf kalo salah

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