Matematika

Pertanyaan

(9-1/100)^3×(9-2/100)^3×(9-3/100)^3×...×(9-2016/100)^3=

NO.3 dan 4 kalo bisa
(9-1/100)^3×(9-2/100)^3×(9-3/100)^3×...×(9-2016/100)^3= NO.3 dan 4 kalo bisa

1 Jawaban

  • Kelas 7 Matematika
    Bab Pola Bilangan

    ^ = pangkat

    3] (9 - 1/100)^3 . (9 - 2/100)^3 . .... . (9 - 2.016/100)^3
    = (9 - 1/100)^3 . (9 - 2/100)^3 . .... . (9 - 900/100) . ... . (9 - 2016/100)
    = ((900 - 1)/100)^3 . ((900 - 2)/100)^3 . ... ((900 - 900)/100)^3 . .... . ((900 - 2016)/100)^3
    = (899/100)^3 . (898/100)^3 . .... . (0/100)^3 . .... . (-1.116/100)^3
    = (899/100)^3 . (898/100)^3 . 0 . ... . (-1.116/100)^3
    = 0

    ✩✩ C ✩✩

    4] 1/2 + 1/6 + 1/12 + ... + 1/9.900 = ?

    1/2

    → 1/(1 . 2)

    1/2 + 1/6
    = 3/6 + 1/6
    = 4/6
    = 2/3

    → 1/6 = 1/(2 . 3)

    1/2 + 1/6 + 1/12
    = 6/12 + 2/12 + 1/12
    = 9/12
    = 3/4

    → 1/12 = 1/(3 . 4)

    Perhatikan polanya

    1/9.900 = 1/(99 . 100)

    Maka

    1/2 + 1/6 + 1/12 + ... + 1/9900
    = 1/(1 . 2) + 1/(2 . 3) + 1/(3 . 4) + ... + 1/(99 . 100)
    = 99/100
    = 0,99

    ✩✩ C ✩✩