(fog)(x)=28-6x dan g(x)=10-2x tentukanlah f(x) pleaseee bantu

(fog) (x) = 28 - 6x
g(x) = 10 - 2x

10 - 2x = a
x = (10 - a) /2

(fog) (x) = 28 - 6x
f(10 - 2x) = 28 - 6x
f(a) = 28 - 6( (10 - a) / 2)
f(a) = 28 - 3(10 - a)
f(a) = 28 - 30 - 3a
f(a) = -2 - 3a
f(x) = -2 - 3x