Tolong kk bantuin pakai cara juga ya kk makasih!!

[tex]d = \sqrt{ {6}^{2} + {4}^{2} } \\ \: \: \: = \sqrt{36 + 16} \\ \: \: \: = \sqrt{52} = 2 \sqrt{13} cm[/tex]


[tex]b = \sqrt{ {3}^{2} + (2 \sqrt{13)} ^{2} } \\ \: \: \: = \sqrt{9 + 52} \\ \: \: \: = \sqrt{61} cm[/tex]