hitunglah luas ∆DEF

[tex] \tan(d) = \frac{8 \sqrt{3} }{x} \\ \tan(60) = \frac{8 \sqrt{3} }{x} \\ \sqrt{3} = \frac{8 \sqrt{3} }{x} \\ \sqrt{3} x = 8 \sqrt{3} \\ x = 8[/tex]
luas segitiga DEF
[tex] \frac{1}{2} \times 8 \times 8 \sqrt{3} = 32 \sqrt{3} {cm}^{2} [/tex]