Diketahui 2x^-x dan g(x) = 3x+4 tentukan nilai fungsi komposisi (fog)(-2),(gof)(1),(fof)(-1),(gog)(2)

fog(-2)= f(g(-2))= 2(g(-2))^-(g(-2))

hitung
g(-2)= 3(-2)+4=-2
sehingga,
fog(-2)= 2(-2)^-(-2)=-4^2=16

gof(1)= g(f(1)) = 3(f(1))+4

hitung
f(1)= 2(1)^-1= 1/2
sehingga,
gof(1)= 3(1/2)+4= 3/2+4= 11/2

fof(-1)= 2(f(-1))^-(f(-1))

hitung
f(-1)= 2(-1)^-(-1)=-2
sehingga,
fof(-1)=2(-2)^-(-2)=16

gog(2)=3(g(2))+4

hitung
g(2)=3(2)+4=10
sehingga,
gog(2)= 2(10)+4=24